Given, C = 63,000, n = 4 years, r = 14% p.a.
∴ i = `"r"/(100) (14)/(100)` = 0.14
Now, P = `"C"/"i" [1 - (1 + "i")^-"n"]`
= `(63000)/(0.14)[1 - (1 + 0.14)^-4]`
= 4,50,000[1 – (1.14)–4]
= 4,50,000[1 – 0.5921]
= 4,50,000(0.4079)
= 1,83,555
∴ Present value of an ordinary annuity is ₹1,83,555.
![Find the present value of an ordinary annuity of ₹63,000 p.a. for 4 years at 14% p.a. compounded annually. [Given (1.14)−4 = 0.5921] - Mathematics and Statistics | Shaalaa.com (2024)](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAQAAAC1HAwCAAAAC0lEQVR42mP8/h8AAvMB+NzmkbcAAAAASUVORK5CYII=)
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