How to Calculate When a Based Is Neutralized With an Acid (2024)

When an acid and a base react with each other, a neutralization reaction occurs, forming a salt and water. The water forms from the combination of the H+ ions from the acid and the OH- ions from the base. Strong acids and strong bases completely dissociate, so the reaction yields a solution with a neutral pH (pH = 7). Because of the complete dissociation of strong acids and bases, if you're given a concentration of an acid or base, you can determine the volume or quantity of the other chemical required to neutralize it. This example problem explains how to determine how much acid is needed to neutralize a known volume and concentration of a base.

Key Takeaways: Acid-Base Neutralization

  • Solving a chemistry problem where a strong acid neutralizes a strong base is straightforward because both the acid and the base completely dissociate.
  • In contrast, neutralization involving a weak acid and/or a weak base requires that you know and use the dissociation constant.
  • Neutralization occurs at the point where the number of moles of H+ equals the number of moles of OH-.

Review of Neutralization Reaction

Neutralization relies on dissociation of an acid and a base. Dissociation is where the acid or base breaks into its component ions. The ions participating in a neutralization reaction are the H+ from the acid and the OH- from the base. The general form of the reaction is:

acid + base → salt + water
AH + B → A + BH

As an example, when hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH), it produces table salt or sodium chloride (NaCl) and water:

HCl + NaOH → NaCl + H2O

Neutralization requires equal amounts of H+ and OH-. So, knowing the volume and concentration of either the acid or base lets you find the volume and concentration of its partner in the reaction.

Solving an Acid-Base Neutralization Problem

What volume of 0.075 M HCl is required to neutralize 100 milliliters of 0.01 M Ca(OH)2 solution?

HCl is a strong acid and will dissociate completely in water to H+ and Cl-. For every mole of HCl, there will be one mole of H+. Since the concentration of HCl is 0.075 M, the concentration of H+ will be 0.075 M.

Ca(OH)2 is a strong base and will dissociate completely in water to Ca2+ and OH-. For every mole of Ca(OH)2 there will be two moles of OH-. The concentration of Ca(OH)2 is 0.01 M so [OH-] will be 0.02 M.

So, the solution will be neutralized when the number of moles of H+ equals the number of moles of OH-.

  • Step 1: Calculate the number of moles of OH-.
  • Molarity = moles/volume
  • moles = Molarity x Volume
  • moles OH- = 0.02 M/100 milliliters
  • moles OH- = 0.02 M/0.1 liters
  • moles OH- = 0.002 moles
  • Step 2: Calculate the Volume of HCl needed
  • Molarity = moles/volume
  • Volume = moles/Molarity
  • Volume = moles H+/0.075 Molarity
  • moles H+ = moles OH-
  • Volume = 0.002 moles/0.075 Molarity
  • Volume = 0.0267 Liters
  • Volume = 26.7 milliliters of HCl

Performing the Calculation

26.7 milliliters of 0.075 M HCl is needed to neutralize 100 milliliters of 0.01 Molarity Ca(OH)2 solution.

The most common mistake people make when performing this calculation is not accounting for the number of moles of ions produced when the acid or base dissociates. It's easy to understand: only one mole of hydrogen ions is produced when hydrochloric acid dissociates, yet also easy to forget it's not a 1:1 ratio with the number of moles of hydroxide released by calcium hydroxide (or other bases with divalent or trivalent cations).

The other common mistake is a simple math error. Make sure you convert milliliters of solution to liters when you calculate the molarity of your solution!

Sources

  • Skoog, D.A; West, D.M.; Holler, J.F.; Crouch, S.R. (2004). Fundamentals of Analytical Chemistry (8th ed.). Thomson Brooks/Cole. ISBN 0-03-035523-0.
  • Snoeyink, V.L.; Jenkins, D. (1980). Aquatic Chemistry: Chemical Equilibria and Rates in Natural Waters. New York: Wiley. ISBN 0-471-51185-4.
  • Trummal, Aleksander; Lipping, Lauri; Kaljurand, Ivari; Koppel, Ilmar A.; Leito, Ivo (2016). "Acidity of Strong Acids in Water and Dimethyl Sulfoxide". The Journal of Physical Chemistry A. 120 (20): 3663–3669. doi:10.1021/acs.jpca.6b02253
  • Zumdahl, Steven S. (2009). Chemical Principles (6th ed.). New York: Houghton Mifflin Company.
How to Calculate When a Based Is Neutralized With an Acid (2024)

FAQs

How to Calculate When a Based Is Neutralized With an Acid? ›

The neutralization of a strong acid and strong base has a pH equal to 7. The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7.

How do you calculate acid-base neutralization? ›

Calculating the Unknown Molarity of an Acid/Base in a Neutralization Reaction:
  1. Take known volume of known solution “A” and multiply it by molarity of solution A to calculate the moles of A.
  2. Next, apply the mole ratio calculation to determine the moles of solution B.

How do you know when an acid or base has been neutralized? ›

The neutralization of a strong acid and strong base has a pH equal to 7. The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7.

How can we detect when an acid has just neutralize a base? ›

So, You can identify a neutralization reaction by :
  1. Looking for salt formed, and it's pH.
  2. Presence of Water 💧💧 H2O.
Oct 20, 2019

What is the formula for the neutralization reaction? ›

The general neutralization equation is H A + B O H → H 2 O + A B . The pH is the measure of a solution's acidity. The following are types of neutralization reactions: Strong acid + strong base = neutral salt water solution (pH = 7)

What is the equation for neutralization of NaOH and HCl? ›

HCl ( aq ) Hydrochloric acid + NaOH ( aq ) Sodium hydroxide → NaCl ( aq ) Sodium chloride + H 2 O ( l ) Water.

How do you calculate moles of acid neutralized? ›

To find the number of moles of acid neutralized by the tablet, the number of moles of acid neutralized in the titration is subtracted from the moles of acid in the initial solution.

When an acid is neutralized by a base What are the products produced? ›

Neutralization is the reaction of an acid and a base, which forms water and a salt.

When an acid is neutralized by a base what is always a product? ›

Acid and base neutralize each other to form a salt and water. Created by Ram Prakash.

How do you neutralize bases? ›

Use a weak acid to neutralize bases. Examples include sodium hydroxide, potassium hydroxide, and ammonia. Many different products aid in the neutralization of acids and bases. They can be as simple as a bag of citric acid or sodium sesquicarbonate, or as complex as a solidifier and neutralizer combined.

What is an example of an acid a base and something neutral? ›

Acids such as HCl (the acid in your stomach that helps you digest your food) or lemon juice are all acids because their pH is lower than 7 (neutral). When you are neutral, you have a pH level of 7, for example water. When you have a basic substance, you are a base with a pH level of 8-16.

How do you predict the products of a neutralization reaction? ›

The product will always be water and a salt composed of the non-proton portion of the acid and the non-hydroxide portion of the base. If a reaction contains either a strong acid or a strong base, the reactants will react to completion, even if the other chemical isn't strong.

What is a neutralization reaction example? ›

Neutralisation Reaction

When a strong acid reacts with a strong base the resultant salt is neither acidic nor basic in nature i.e. it is neutral. For example when HCl (Hydrochloric acid), a strong acid, reacts with NaOH, a strong base, the resulting salt is sodium chloride and water.

What is M1 V1 M2 V2? ›

Remember M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the concentration after mixing or diluting, and V2 is the total final volume. When you are dealing with dilute aqueous solutions, V2 is the sum of the volumes that were mixed. Note that in this equation the volumes cancel.

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